Find Duplicate

 

You have been given an integer array/list(ARR) of size N which contains numbers from 0 to (N - 2). Each number is present at least once. That is, if N = 5, the array/list constitutes values ranging from 0 to 3 and among these, there is a single integer value that is present twice. You need to find and return that duplicate number present in the array.

Sample Input 1:
9
0 7 2 5 4 7 1 3 6
Sample Output 1:
7

public class Solution{  
    
    public static int duplicateNumber(int arr[]) {
  
        for(int i=0;i<arr.length;i++)
        {
            for(int j=0;j<arr.length;j++)
            {
                if(i!=j && arr[i]==arr[j])
                {
                    return arr[i];
                }
            }
        }
        return -1;
    }
}

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